Usoro mgbako HVAC

微信截图_20220628084907

I, Okpomọkụ:

Celsius (C) na Fahrenheit (F)

Fahrenheit = 32 + Celsius × 1.8

Celsius = (Fahrenheit -32) /1.8

Kelvin (K) na Celsius (C)

Kelvin (K) = Celsius (C) +273.15

II, Ntugharị nrụgide:

Mpa,kpa,pa,bar

1Mpa=1000Kpa;

1Kpa = 1000pa;

1 Mpa = 10 mmanya;

1 mmanya = 0.1Mpa = 100Kpa;

1 ikuku = 101.325Kpa = 1 mmanya = 1 kilogram;

1 mmanya = 14.5psi;

1psi = 6.895Kpa;

1 n'arọ / cm2 = 105 = 10 mH2O = 1 mmanya = 0.1 MPa

1 Pa=0.1 mmH2O=0.0001 mH2O

1 mH2O = 104 Pa = 10 kPa

III, Ọsọ ifufe, ntụgharị olu

1CFM =1.699 M³/H=0.4719 l/s

1M³/H=0.5886CFM

1l/s=2.119CFM

1FPM=0.3048 m/min=0.00508 m/s

IV, ike na ike jụrụ oyi:

1KW=1000 W

1KW = 861Kcal / h = 0.39 P (ike jụrụ oyi)

1W= 1 J/s

1USTR = 3024Kcal / h = 3517W (ikike jụrụ oyi)

1BTU=0.252kcal/h=1055J

1BTU/H=0.252kcal/h

1BTU/H = 0.2931W (ike jụrụ oyi)

1MTU/H = 0.2931KW (ike jụrụ oyi)

1HP (ọkụ eletrik) = 0.75KW (ọkụ eletrik)

1KW (ọkụ eletrik) = 1.34HP (ọkụ eletrik)

1RT (ike jụrụ oyi) = 3.517KW (ike jụrụ oyi)

1KW (Ike jụrụ oyi)= 3.412MBH

1P (ikike jụrụ oyi)=2200kcal/h=2.56KW

1kcal/h = 1.163W

V,Ntụ oyiọkpụrụkpụ nwụnye na ike jụrụ oyi:

1.5mm2=12A-20A (2650~4500W) 1P ~ 2P

2.5mm2=20-25A (4500~5500W) 2P

4mm2=25-32A (5500~7500W) 2P ~ 3P

6mm2=32-40A (7500~8500W) 3P ~ 4P

VI, usoro mgbako refrigerant:

1, Nhọrọ nke ịgbasa valvụ: oyi ton + 1.25% ohere

2, Pịa ike: 1P = 0.735kW

3, Refrigerant ụgwọ: ike jụrụ (KW) ÷3.516 x 0.58

4, Mmiri eruba nke ikuku ngwa nju oyi: jụrụ ikike (KW) ÷ okpomọkụ iche ÷1.163

5, jụrụ mmiri eruba ọnụego nke mmiri jụrụ ịghasa igwe: jụrụ ike (KW) ×0.86÷ okpomọkụ iche.

6, jụrụ mmiri eruba ọnụego nke mmiri jụrụ ịghasa igwe:(ike jụrụ oyiKW+ pịa ike) ×0.86÷ okpomọkụ dị iche

7, Gross kpo oku uru QT = QS + QL

8, Ikuku jụrụ: QT = 0.24 * ∝ * L * (h1-h2)

9, Mkpa okpomọkụ ikuku jụrụ: QS = Cp * ∝ * L * (T1-T2)

10, Latent okpomọkụ nke ikuku jụrụ: QL = 600 * ∝ * L * (W1-W2)

11,Mmiri oyiolu:L/sV1= Q1/(4.187△T1)

12, Igwe mmiri jụrụ oyi: L/sV2=Q2/(4.187△T2)=(3.516+KW/TR)TR,Q2=Q1+N=TR*3.516+KW/TR*TR=(3.516+KW/TR) *TR

13, Refrigeration arụmọrụ: EER = Refrigeration ikike (Mbtu / h) / ike oriri (KW);COP= Ike refrigeration (KW)/ oriri ike (KW)

14, Partial jụrụ ibu ọrụ: NPLV = 1 / (0.01 / A + 0.42 / B + 0,45 / C + 0.12 / D)

15, Full ibu ugbu a (atọ na-adọ): FLA = N / √3 UCOSφ

16, Igwe ikuku ọhụrụ: Lo=nV

17, Ikukuọkọnọ olu: L=Qs/〔Cp*∝*(T1-T2)〕

18, ike nke fan: N1 = L1 * H1 / (102 * n1 * n2)

19, Ike nke mmiri mgbapụta: N2 = L2 * H2 * r / (102 * n3 * n4)

20, The ọkpọkọ dayameta: D = √4 * 1000L2 / (π * v)

21, Mpaghara eriri: F = a * b * L1 / (1000u)


Oge nzipu: Jun-28-2022